Q. The efficiency of a Carnot engine working between 800 K and 500 K is
A) 0.4
B) 0.625
C) 0.375
D) 0.5
Explanation
(c) $\eta = 1 - \frac{T_{2}}{T_{1}} - 1 - \frac{500}{800} = \frac{3}{8} = 0.375$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.