Q.
A thermodynamical system is taken from state $A$ to state $B$ along $ACB$ and is brought back to $A$ along $BDA$ as shown in figure. Net work done during one complete cycle is given by area.
A) $ACBDA$
B) $ACB\ p_{2}p_{1}A$
C) $A\ V_{1}\ V_{2}\ BDA$
D) $BD\ Ap_{1}p_{2}\ B$
Explanation
(a) In a cycle process, work done is equal to area of the loop $ACBDA$, representing the cycle of changes
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.