Q. Temperature of an ideal gas is 300 K. The change in temperature of the gas when its volume changes from $V$ to $2V$ in the process $p = \alpha V$ (here $\alpha$ is a positive constant) is

A) 900 K
B) 1200 K
C) 600 K
D) 300 K
Explanation

(b) The given relation is $p \propto V$
Therefore, $p \propto V$
When $V$ chnages from $V$ to $2V$, pressure $p$ is also doubled
For an ideal gas, $\frac{pV}{T} =$constant
$\therefore\ T \propto pv$. Hence, $T$ becomes $2 \times 2 = 4$ times
$ie,\ 4 \times 300\ K = 1200\ K$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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