Q. When a small amount of heat $\mathrm{\Delta}Q$ is added to an enclosed gas, then increase in internal energy and external work done are related as
A) $mC_{v}\mathrm{\Delta}T = Q + p\mathrm{\Delta}V$
B) $\mathrm{\Delta}Q = mC_{v}\mathrm{\Delta}T + p\mathrm{\Delta}V$
C) $mC_{v} = \mathrm{\Delta}Q + p\mathrm{\Delta}V$
D) $\mathrm{\Delta}Q = mC_{p}\mathrm{\Delta}T + p\mathrm{\Delta}V$
Explanation
(b) $\mathrm{\Delta}Q = \mathrm{\Delta}U + \mathrm{\Delta}W = mC_{v}(\mathrm{\Delta}T) + p(\mathrm{\Delta}V)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.