Q. A Carnot engine takes heat from a reservoir at $627℃$ and rejects heat to a sink at $27℃.$ Its efficiency will be
A) 3/5
B) 1/3
C) 2/3
D) 200/209
Explanation
(c) Efficiency, $\ \ \ \eta = 1 - \frac{T_{2}}{T_{1}}$
$\therefore\ \ \ \ \eta = 1 - \frac{(27 + 273)}{(273 + 627)}$
$\ \ \ \ \ \ \ \ \ \ \ = 1 - \frac{300}{900} = \frac{600}{900} = \frac{2}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.