Q. The efficiency of Carnot’s heat engine is 0.5, when the temperature of the source is $T_{1}$and that of sink is $T_{2}.$The efficiency of anther Carnot’s heat engine is also 0.5. The temperature of source and sink of the second engine are respectively
A) $2T_{1},2T_{2}$
B) $2T_{1},\frac{T_{2}}{2}$
C) $T_{1} + 5,\ T_{2} - 5$
D) $T_{1} + 10,\ T_{2} - 10$
Explanation
(a) Efficiency of Carnot’s heat engine, $\eta = 1 - \frac{T_{2}}{T_{1}}$
Efficiency remains same when both $T_{1}\ and\ T_{2}$ are increased by same factor.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.