Q. If heat $Q$ is added reversibly to a system at temperature $T$ and heat $Q'$ is taken away from it reversibly at temperature $T'$, then which one of the following is correct
A) $\frac{Q}{T} - \frac{Q^{'}}{T} = 0$
B) $\frac{Q}{T} - \frac{Q^{'}}{T} > 0$
C) $\frac{Q}{T} - \frac{Q^{'}}{T} < 0$
D) $\frac{Q}{T} - \frac{Q^{'}}{T} =$ change in internal energy of the system
Explanation
The correct answer is Option A: $\frac{Q}{T} - \frac{Q^{'}}{T} = 0$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.