Q. The temperature of reservoir of Carnot’s engine operating with an efficiency of 70% is $1000K$. The temperature of its sink is
A) $300\ K$
B) $400\ K$
C) $500\ K$
D) $700\ K$
Explanation
(a) $\eta = 1 - \frac{T_{2}}{T_{1}} \Rightarrow \frac{70}{100} = 1 - \frac{T_{2}}{1000} \Rightarrow T_{2} = 300\ K$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.