Q. The coefficient of performance of a refrigerator work between $10℃$ and $20℃$ is
A) 28.3
B) 29.3
C) 2
D) Cannot be calculated
Explanation
(a) $T_{1} = 273 + 20 = 293\ K,\ T_{2} = 273 + 10 = 283\ K$
Coefficient of performance
$= \frac{T_{2}}{T_{1} - T_{2}} = \frac{283}{293 - 283} = \frac{283}{10} = 28.3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.