Q. The p-V diagram of a system undergoing thermodynamic transformation is shown in figure. The work done by the system in going from $A \rightarrow B \rightarrow C$ is 30 J, and 40 J heat is given to the system. The change in internal energy between A and C is

A) 10 J
B) 70 J
C) 84 J
D) 134 J
Explanation

(a) Since, work is done by the system, so it is positive. Therefore,
$\mathrm{\Delta}W = 30J$
Heat given to the system,
$\mathrm{\Delta}Q = 40J$
According to first law of thermodynamics, change in internal energy is given by
$\mathrm{\Delta}U = \mathrm{\Delta}Q - \mathrm{\Delta}W$
$= 43 - 30 = 10\ J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Thermodynamics MCQs