Q. Two soap bubbles of radii x and y coalesce to constitute a bubble of radius z. Then is equal to

A) $\sqrt{x^{2} + y^{2}}$
B) $\sqrt{x + y}$
C) $x + y$
D) $\frac{x + y}{2}$
Explanation

(a) $n = n_{1} + n_{2}$
$pV = p_{1}V_{1} + p_{2}V_{2}$
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$p_{1} = p_{0} + \frac{4T}{x},\ p_{2} = p_{0} + \frac{4T}{y},\ p = p_{0} + \frac{4T}{z}$
If the process takes place is vacuum then $p_{0} = 0$
$p_{1} = \frac{4T}{x},\ p_{2} = \frac{4T}{y},\ p = \frac{4T}{z}$
If process is isothermal
$\therefore\ \ \ \ \ p_{1}V_{1} + p_{2}V_{2} = pV$
$\therefore\ \ \ \ \ \ z = \sqrt{x^{2} + y^{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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