Q. Work done per mol in an isothermal change is
A) $RT\log_{10}\frac{V_{2}}{V_{1}}$
B) $RT\log_{10}\frac{V_{1}}{V_{2}}$
C) $RT\log_{e}\frac{V_{2}}{V_{1}}$
D) $RT\log_{e}\frac{V_{1}}{V_{2}}$
Explanation
(c) For isothermal process $PV = RT\ \Rightarrow P = \frac{RT}{V}$
$\therefore W = PdV = \int_{V_{1}}^{V_{2}}\frac{RT}{V}dV = RT\log_{e}\frac{V_{2}}{V_{1}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.