Q. Adiabatic modulus of elasticity of a gas is $2.1 \times 10^{5}Nm^{- 2}.$ What will be its isothermal modulus of elasticity? $\left( \frac{C_{p}}{C_{v}} = 1.4 \right)$
A) $1.2 \times 10^{5}\ Nm^{- 2}$
B) $4 \times 10^{5}\ Nm^{- 2}$
C) $1.5 \times 10^{5}\ Nm^{- 2}$
D) $1.8 \times 10^{5}\ Nm^{- 2}$
Explanation
(c) $\frac{E_{s}}{E_{T}} = \gamma = \frac{C_{P}}{C_{V}} = 1.4$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{2.1 \times 10^{5}}{E_{T}} = 1.4$
$or\ \ \ \ \ \ E_{T} = \frac{2.1 \times 10^{5}}{1.4}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 1.5 \times 10^{5}\ \ Nm^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.