When a system is taken from state $i\ $to state $f$ along the path $iaf$, it is found that Q=50 cal and W=20 cal. Along the path $ibf$, Q=36 cal. W along the path $ibf$ is

Question

Dr. Abubacker · Accepted Answer

(a) From first law of thermodynamics,
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Q = \mathrm{\Delta}U + W$
For path iaf,
$50 = \mathrm{\Delta}U + 20$
$	herefore\ \ \ \ \ \ \ \mathrm{\Delta}U = U_{f} - U_{i} = 30\ cal$
For path ibf,
$Q = \mathrm{\Delta}U + W$
or $W = Q - \mathrm{\Delta}U$
=36-30=6cal

Q. When a system is taken from state $i\ $to state $f$ along the path $iaf$, it is found that Q=50 cal and W=20 cal. Along the path $ibf$, Q=36 cal. W along the path $ibf$ is

Explanation

Reviewed by Dr. Abubacker

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