Q. The latent heat of vaporization of water is $2240\ J/g$. If the work done in the process of expansion of $1\ g$ is $168\ J$, then increase in internal energy is
A) $2408\ J$
B) $2240\ J$
C) $2072\ J$
D) $1904\ J$
Explanation
(c) $\mathrm{\Delta}Q = \mathrm{\Delta}U + \mathrm{\Delta}W \Rightarrow \mathrm{\Delta}U = \mathrm{\Delta}Q - \mathrm{\Delta}W = 2240 - 168 = 2072\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.