Q. A system changes from the state $(P_{1},V_{1})$ to $(P_{2}V_{2})$ as shown in the figure. What is the work done by the system
A) $7.5 \times 10^{5}\ joule$
B) $7.5 \times 10^{5}\ erg$
C) $12 \times 10^{5}\ joule$
D) $6 \times 10^{5}\ joule$
Explanation
(c) Work done = Area of $PV$ graph (here trapezium)
$= \frac{1}{2}\left( 1 \times 10^{5} + 5 \times 10^{5} \right) \times (5 - 1) = 12 \times 10^{5}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.