Q. Four engines are working between the given temperatures ranges given below. For which temperature range the efficiency is maximum
A) 100 K, 80 K
B) 40 K, 20 K
C) 60 K, 40 K
D) 120 K, 100 K
Explanation
(b) $\eta = 1 - \frac{T_{2}}{T_{1}} = \frac{T_{1} - T_{2}}{T_{1}}$
In all the four cases, $T_{1} - T_{2} = 20$ K. Therefore, $\eta$ is highest, when $T_{1}$ is lowest
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.