Q. A mass of dry air at NTP. is compressed to $\frac{1}{20}$ th of its original volume suddenly. If $\gamma = 1.4$, the final pressure would be
A) 20 atm
B) 66.28 atm
C) 30 atm
D) 150 atm
Explanation
(b) From $p_{2}V_{2}^{\gamma} = p_{1}V_{1}^{\gamma}$
$p_{2} = p_{1}\left( \frac{V_{1}}{V_{2}} \right)^{\gamma} = 1\left( \frac{V_{1}}{1/20V_{1}} \right)^{1.4}$
$= 66.28$ atm
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.