Q. The efficiency of Carnot engine when source temperature is $T_{1}$ and sink temperature is $T_{2}$ will be
A) $\frac{T_{1} - T_{2}}{T_{1}}$
B) $\frac{T_{2} - T_{1}}{T_{2}}$
C) $\frac{T_{1} - T_{2}}{T_{2}}$
D) $\frac{T_{1}}{T_{2}}$
Explanation
The correct answer is Option A: $\frac{T_{1} - T_{2}}{T_{1}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.