Q. By what percentage should the pressure of the given mass of gas be increased so to decrease its volume by 10% at a constant temperature?
A) 5%
B) 7.2%
C) 12.5%
D) 11.1%
Explanation
(d) When $T$ is constant, $pV =$ constant
When volume is decreased by 10% $ie$, volume become $\frac{90}{100}$, the pressure must become 100/90
$\therefore$ % increase in pressure$= \frac{(100 - 90) \times 100}{90} = 11.1\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.