(d) $\frac{1}{2}Mv^{2} = C_{V}.\mathrm{\Delta}T$ $\frac{1}{2}Mv^{2} = \frac{R}{\gamma - 1}.\mathrm{\Delta}T \Rightarrow \mathrm{\Delta}T = \frac{M.v^{2}(\gamma - 1)}{2R} = \frac{(\gamma - 1)Mv^{2}}{2R}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.