Q. Which of the following graphs correctly represents the variation of $\beta = - (dV/dP)V$ with $P$ for an ideal gas at constant temperature
A)
B)
C)
D)
Explanation
(a) For an isothermal process $PV =$ constant
$\Rightarrow PdV + VdP = 0 \Rightarrow - \frac{1}{V}\left( \frac{dV}{dP} \right) = \frac{1}{P}$
So, $\beta = \frac{1}{P}\ \therefore$ graph will be rectangular hyperbola
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.