Q. A gas expands under constant pressure $P$ from volume $V_{1}$ to $V_{2}$. The work done by the gas is

A) $P(V_{2} - V_{1})$
B) $P(V_{1} - V_{2})$
C) $P(V_{1}^{\gamma} - V_{2}^{\gamma})$
D) $P\frac{V_{1}V_{2}}{V_{2} - V_{1}}$
Explanation

(a) Work done $= P\mathrm{\Delta}V = P(V_{2} - V_{1})$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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