Q. For which combination of working temperatures the efficiency of Carnot’s engine is highest
A) $80\ K,60\ K$
B) $100\ K,\ 80\ K$
C) $60\ K,\ 40\ K$
D) $40\ K,\ 20\ K$
Explanation
(d) $\eta = 1 - \frac{T_{2}}{T_{1}};$ for $\eta$ to be max. ratio $\frac{T_{2}}{T_{1}}$ should be min
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.