Q. A thermodynamic system undergoes cyclic process $ABCDA$ as shown in figure. The work done by the system is
A) $P_{0}V_{0}$
B) $2P_{0}V_{0}$
C) $\frac{P_{0}V_{0}}{2}$
D) Zero
Explanation
(d) $W_{BCOB} = -$ Area of triangle $BCO = - \frac{P_{0}V_{0}}{2}$
$W_{AODA} = +$ Area of triangle $AOD = + \frac{P_{0}V_{0}}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.