In a refrigerator, the low temperature coil of evaporator is at $- 23℃$ and the compressed gas in the condenser has a temperature of $77℃$. How, much electrical energy is spent in freezing 1 kg of water already at $0℃$?

Question

Dr. Abubacker · Accepted Answer

(a) COP$= \frac{T_{2}}{T_{1} - T_{2}} = \frac{273 - 23}{(273 + 77) - (273 - 23)} = \frac{250}{100} = 2.5$
As COP$= \frac{Q_{2}}{W}$
$	herefore\ 2.5 = \frac{1000 	imes 80 	imes 4.2}{W}$
or $W = \frac{1000 	imes 80 	imes 4.2}{2.5} = 134400\ J$

Q. In a refrigerator, the low temperature coil of evaporator is at $- 23℃$ and the compressed gas in the condenser has a temperature of $77℃$. How, much electrical energy is spent in freezing 1 kg of water already at $0℃$?

Explanation

Reviewed by Dr. Abubacker

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