Q. For an engine operating between $t_{1}℃$ and $t_{2}℃$, the efficiency will be
A) $\frac{t_{1}}{t_{2}}$
B) $1 - \frac{t_{2}}{t_{1}}$
C) $\frac{t_{1} - t_{2}}{t_{2}}$
D) $\frac{t_{1} - t_{2}}{t_{1} + 273}$
Explanation
(d) $\eta_{1} = \frac{T_{1} - T_{2}}{T_{1}} = \frac{\left( t_{1} + 273 \right) - (t_{2} + 273)}{t_{1} + 273}$
$= \frac{t_{1} - t_{2}}{t_{1} + 273}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.