Q. One mole of a monoatomic gas is heated at a constant pressure of $1\ atm$ from 0 K to 100 K. If the gas constant $R = 8.32\ Jmol^{- 1}K^{- 1}$, the change in internal energy of the gas is approximately
A) 2.3 J
B) 46 J
C) $8.67 \times 10^{3}$ J
D) $1.25 \times 10^{3}$ J
Explanation
(d) $dU = C_{v}dT = \left( \frac{3}{2}R \right)dT = \frac{3}{2} \times 8.32 \times 100 = 1.25 \times 10^{3}$ J
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.