(c) $\mathrm{\Delta}Q = \mathrm{\Delta}U + \mathrm{\Delta}W = 0 \Rightarrow \mathrm{\Delta}W = - \mathrm{\Delta}U$
If $\mathrm{\Delta}W$ is positive $i.e.,$ gas does work then $\mathrm{\Delta}U$ should be negative meaning internal energy is used in doing work