Q. If $\gamma = 2.5$ and volume is equal to $\frac{1}{8}$ times to the initial volume then pressure $P$ is equal to (initial pressure $= P$)
A) $P^{'} = P$
B) $P' = 2P$
C) $P^{'} = P \times (2)^{15/2}$
D) $P^{'} = 7P$
Explanation
(c) $\frac{P_{2}}{P_{1}} = \left( \frac{V_{1}}{V_{2}} \right)^{\gamma} \Rightarrow \frac{P^{'}}{P} = (8)^{5/2} \Rightarrow P^{'} = P \times (2)^{15/2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.