Q. An ideal gas of mass $m$ in a state $A$ goes to another state $B$ via three different processes as shown in figure. If $Q_{1},Q_{2}$ and $Q_{3}$ denote the heat absorbed by the gas along the three paths, then
A) $Q_{1} < Q_{2} < Q_{3}$
B) $Q_{1} < Q_{2} = Q_{3}$
C) $Q_{1} = Q_{2} > Q_{3}$
D) $Q_{1} > Q_{2} > Q_{3}$
Explanation
(a) Initial and final states are same in all the process
Hence $\mathrm{\Delta}U = 0$; in each case
By FLOT; $\mathrm{\Delta}Q = \mathrm{\Delta}W =$ Area enclosed by curve with volume axis
$\because(Area)_{1} < (Area)_{2} < (Area)_{3} \Rightarrow Q_{1} < Q_{2} < Q_{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.