Q. One mole of an ideal monoatomic gas is heated at a constant pressure of 1 atm from $0℃$ to $100℃$. Work done by the gas is
A) $8.31 \times 10^{3}$ J
B) $8.31 \times 10^{- 3}$ J
C) $8.31 \times 10^{- 2}$ J
D) $8.31 \times 10^{2}$ J
Explanation
(d) $dW = dQ - dU$
$= C_{2}\left( T_{2} - T_{1} \right) - C_{v}\lbrack\ T_{2} - T_{1}\ \rbrack$
$= R\left\lbrack T_{2} - T_{1} \right\rbrack$
$= 8.31 \times 100 = 8.31 \times 10^{2}\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.