One mole of an ideal gas expands at a constant temperature of $300\ K$ from an initial volume of $10\ litres$ to a final volume of $20\ litres$. The work done in expanding the gas is $(R = 8.31\ J/mole$-$K)$

Question

Dr. Abubacker · Accepted Answer

(b) $W_{iso} = \mu RT\log_{e}\frac{V_{2}}{V_{1}} = 1 	imes 8.31 	imes 300\log_{e}{\frac{20}{10} = 1728J}$

Q. One mole of an ideal gas expands at a constant temperature of $300\ K$ from an initial volume of $10\ litres$ to a final volume of $20\ litres$. The work done in expanding the gas is $(R = 8.31\ J/mole$-$K)$

Explanation

Reviewed by Dr. Abubacker

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