Q. Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from $2 \times 10^{- 3}m^{3}$ to $3.34m^{3}$. The work done by the system is about
A) $- 340\ kJ$
B) $- 170\ kJ$
C) $170\ kJ$
D) $340\ kJ$
Explanation
(d) $W = P\mathrm{\Delta}V = 1.01 \times 10^{5}(3.34 - 2 \times 10^{- 3})$
$= 337 \times 10^{3}J = 340\ kJ$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.