Q. When heat energy of $1500\ joules$, is supplied to a gas at constant pressure $2.1 \times 10^{5}N/m^{2}$, there was an increase in its volume equal to $2.5 \times 10^{- 3}N/m^{2}$. The increase in internal energy of the gas in joules is

A) 450
B) 525
C) 975
D) 2025
Explanation

(c) According to FLOT
$\mathrm{\Delta}Q = \mathrm{\Delta}U + P(\mathrm{\Delta}V) \Rightarrow \mathrm{\Delta}U = \mathrm{\Delta}Q - P(\mathrm{\Delta}V)$
$= 1500 - \left( 2.1 \times 10^{5} \right)\left( 2.5 \times 10^{- 3} \right) = 975\ joule$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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