Q. A reversible heat engine converts $\frac{1}{6}$ th of heat it absorbs from source into work. When temperature of source is 600 K, temperature at which heat exhausts is
A) 500 K
B) 100 K
C) 0 K
D) 600 K
Explanation
(a) $\eta = 1 - \frac{T_{2}}{T_{1}}$ or $\frac{T_{2}}{T_{1}} = 1 - \eta = 1 - \frac{1}{6} = \frac{5}{6}$
$T_{2} = \frac{5}{6}T_{1} = \frac{5}{6} \times 600 = 500\ K$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.