Q. A sample of gas is at $0℃.$ To what temperature it must be raised in order to double the $r.m.s.$ speed of the molecule
A) $270℃$
B) $819℃$
C) $1090℃$
D) $100℃$
Explanation
(b) $v_{rms} \propto \sqrt{T};$ To double the $rms$ velocity temperature should be made four times, $i.e.,$
$T_{2} = 4T_{1} = 4(273 + 0) = 1092K = 819℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.