Q. The temperature of an ideal gas is increased from $27℃$ to $127℃,$ then percentage increase in $V_{rms}$ is
A) 37%
B) 11%
C) 33%
D) 15.5%
Explanation
(d) $V_{rms} = \sqrt{\frac{3RT}{M}}$
% increase in $V_{rms} = \frac{\sqrt{\frac{3RT_{2}}{M}} - \sqrt{\frac{3RT_{1}}{M}}}{\sqrt{\frac{3RT_{1}}{M}}} \times 100\%$
$= \frac{20 - 17.32}{17.32} \times 100 = 15.5\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.