Q. Pressure versus temperature graph of an ideal gas at constant volume $V$ of an ideal gas is shown by the straight line $A.$ Now mass of the gas is doubled and the volume is halved, then the corresponding pressure versus temperature graph will be shown by the line
A) $A$
B) $B$
C) $C$
D) None of these
Explanation
(b) $P = \frac{\mu RT}{V} = \frac{mRT}{MV}\ \ \ \ \left( \mu = \frac{m}{M} \right)$
So, at constant volume pressure-versus temperature graph is a straight line passing through origin with slope $\frac{mR}{MV}.$ As the mass is doubled and volume is halved slope becomes four times. Therefore, pressure versus temperature graph will be shown by the line $B$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.