Q. The ratio of root mean square velocity of $O_{3}\ and\ O_{2}$ is

A) $1:1$
B) $2:3$
C) $3:2$
D) $\sqrt{2}\ :\sqrt{3}$
Explanation

(d) Root mean square velocity of gas molecules
$v_{rms} = \sqrt{\frac{3RT}{M}}\ \ \ \ \ \ \ $
$or\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v_{rms} \propto \frac{1}{\sqrt{M}}\ \ \ \ \ \ $
$or\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{{v_{O}}_{3}}{{v_{O}}_{2}} = \sqrt{\frac{{M_{O}}_{2}}{{M_{O}}_{3}}}$
Here, ${M_{O}}_{2} = 32,\ \ \ \ \ {M_{O}}_{3} = 48$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{{v_{O}}_{3}}{{v_{O}}_{2}} = \sqrt{\frac{32}{48}} = \frac{\sqrt{2}}{\sqrt{3}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Kinetic Theory MCQs