(a) Average kinetic energy $E = \frac{f}{2}kT = \frac{3}{2}kT$ $\Rightarrow E = \frac{3}{2} \times \left( 1.38 \times 10^{- 23} \right)(273 + 30) = 6.27 \times 10^{- 21}J$ $= 0.039eV < 1\ eV$
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