Q. The kinetic energy of one mole gas at $300K$ temperature, is $E.$ At $400\ K$ temperature kinetic energy is $E^{'}.$ The value of $E^{'}/E$ is
A) $1.33$
B) $\sqrt{\left( \frac{4}{3} \right)}$
C) $\frac{16}{9}$
D) $2$
Explanation
(a) $E = \frac{3}{2}RT \Rightarrow \frac{E^{'}}{E} = \frac{T^{'}}{T} = \frac{400}{300} = \frac{4}{3} = 1.33$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.