Q. The average translational kinetic energy of a hydrogen gas molecules at NTP will be [Boltzmann’s constant $k_{B} = 1.38 \times 10^{- 23}J/K$]
A) $0.186 \times 10^{- 20}Joule$
B) $0.372 \times 10^{- 20}Joule$
C) $0.56 \times 10^{- 20}Joule$
D) $5.6 \times 10^{- 20}Joule$
Explanation
(c) $E_{av} = \frac{f}{2}kT = \frac{3}{2} \times 1.38 \times 10^{- 23} \times 273 = 0.56 \times 10^{- 20}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.