Q. The temperature of an ideal gas is reduced from $927℃$ to $27℃.$ The $r.m.s.$ velocity of the molecules becomes
A) Double the initial value
B) Half of the initial value
C) Four times the initial value
D) Ten times the initial value
Explanation
(b) Temperature becomes $\frac{1}{4}th$ of initial value $\lbrack 1200K = 927℃ \rightarrow 300K = 27℃\rbrack$
So, using $v_{rms} \propto \sqrt{T}.\ r.m.s.$ velocity will be half of the initial value
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.