Q. Figure shows two flasks connected to each other. The volume of the flask 1 is twice that of flask 2. The system is filled with an ideal gas at temperature $100\ K$ and $200\ K$ respectively. If the mass of the gas in 1 be $m$ then what is the mass of the gas in flask 2
A) $m$
B) $m/2$
C) $m/4$
D) $m/8$
Explanation
(c) $PV = \frac{m}{M}RT \Rightarrow V \propto mT \Rightarrow \frac{V_{1}}{V_{2}} = \frac{m_{1}}{m_{2}}.\frac{T_{1}}{T_{2}}$
$= \frac{2V}{V} = \frac{m}{m_{2}} \times \frac{100}{200} \Rightarrow m_{2} = \frac{m}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.