Q. The quantity of heat required to raise one mole through one degree kelvin for a monoatomic gas at constant volume is

A) $\frac{3}{2}R$
B) $\frac{5}{2}R$
C) $\frac{7}{2}R$
D) $4R$
Explanation

(a) $(\mathrm{\Delta}Q)_{V} = \mu C_{V}\mathrm{\Delta}T \Rightarrow (\mathrm{\Delta}Q)_{V} = 1 \times C_{V} \times 1 = C_{V}$
For monoatomic gas $C_{V} = \frac{3}{2}R$
$\therefore(\mathrm{\Delta}Q)_{V} = \frac{3}{2}R$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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