(a) $(\mathrm{\Delta}Q)_{V} = \mu C_{V}\mathrm{\Delta}T \Rightarrow (\mathrm{\Delta}Q)_{V} = 1 \times C_{V} \times 1 = C_{V}$ For monoatomic gas $C_{V} = \frac{3}{2}R$ $\therefore(\mathrm{\Delta}Q)_{V} = \frac{3}{2}R$
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Ph.D. in Physics with 19+ years of teaching experience.