Q. The pressure and temperature of two different gases is $P$ and $T$ having the volume $V$ for each. They are mixed keeping the same volume and temperature, the pressure of the mixture will be
A) $P/2$
B) $P$
C) $2P$
D) $4P$
Explanation
(c) $\mu_{1} = \frac{PV}{RT},\mu_{2} = \frac{PV}{RT}$
$P^{'} = \frac{(\mu_{1} + \mu_{2})RT}{V} = \frac{2PV}{RT} \times \frac{RT}{V} = 2P$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.