Q. A solid whose volume does not change with temperature floats in liquid. For two different temperatures$t_{1}\ and\ t_{2}$, the fractions $f_{1}\ and\ f_{2}$ of volume of solid remain submerged. What is the coefficient of volume expansion of liquid?

A) $\frac{f_{1} - f_{2}}{f_{2}t_{1} - f_{1}t_{2}}$
B) $\frac{f_{1} - f_{2}}{f_{1}t_{1} - f_{2}t_{2}}$
C) $\frac{f_{1} + f_{2}}{f_{2}t_{1} - f_{1}t_{2}}$
D) $\frac{f_{1} + f_{2}}{f_{1}t_{1} - f_{2}t_{2}}$
Explanation

(a) Let $V$ be the volume of solid ; $d$ be its density and $m$ be its mass ; if g coefficient of volume expansion of liquid, then
Density at temperature $t_{1}\ is,\ d_{1} = \frac{d_{0}}{1 + \gamma t_{1}}$
Density at temperature $t_{2}\ is,\ d_{2}$ = $\frac{d_{0}}{1 + \gamma t_{2}}$
According to Archimede’s principle,
$f_{1}V\ d_{1} = m = f_{2}\ Vd_{2}$
Or $\frac{d_{1}}{d_{2}}\ = \frac{f_{2}}{f_{1}} = \ \frac{d_{0}}{\left( 1 + \gamma t_{1} \right)}\frac{\left( 1 + \gamma t_{2} \right)}{d_{0}}$
Or $f_{1} + f_{1}\gamma t_{2} = f_{2} + f_{2}\ \gamma t_{1}$
$f_{1} - f_{2}\ = \ \gamma\left( f_{2}t_{1} - f_{1}t_{2} \right)$
$\gamma\ = \ \frac{(f_{1} - f_{2})}{f_{2}t_{1} - f_{1}t_{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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