Q. The $r.m.s.$ speed of gas molecules is given by
A) $2.5\sqrt{\frac{RT}{M}}$
B) $1.73\sqrt{\frac{RT}{M}}$
C) $2.5\sqrt{\frac{M}{RT}}$
D) $1.73\sqrt{\frac{M}{RT}}$
Explanation
(b) $v_{rms} = \sqrt{\frac{3RT}{M}} = \sqrt{3}\sqrt{\frac{RT}{M}} = 1.73\sqrt{\frac{RT}{M}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.