Q. The coefficiency of apparent expansion of a liquid when determined using two different vessels $A\ and\ B\ are\ \lambda_{1}$ and $\lambda_{2},$ respectively. If the coefficient of linear expansion of the vessel $A\ is\ \alpha,\ $the coefficient of linear expansion of vassel $B$ is
A) $\frac{\alpha\gamma_{1}\ \gamma_{2}}{\gamma_{1} + \gamma_{2}}$
B) $\frac{\gamma_{1} - \gamma_{2}}{2\alpha}$
C) $\frac{\gamma_{1} - \gamma_{2} + \alpha}{3\alpha}$
D) $\frac{\gamma_{1} - \gamma_{2}}{3} + \alpha$
Explanation
(d) Using $\gamma_{r} = \gamma_{a} +$ g, we get
$\gamma_{r}\ = \ \gamma_{1} + 3\alpha = \ \gamma_{2} + 3\beta$
$\therefore\ \beta = \ \frac{\gamma_{1} - \gamma_{2}}{3} + \ \alpha$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.